Ten cars containing a total of 32 people passed through a checkpoint. If none of these cars contained more than 4 people, what is the greatest possible number of these cars that could have contained exactly 2 people?
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Just things I wonder about ... and some people are nice enough to answer. You are welcome to answer, too ... just click on "Comments" and off you go! IF you don't want to be Anonymous, use the Name/URL option and just put in your name ... no URL required .... Starting Jan 28th, 2009, I am using questions from "Table Topics: Right or Wrong?"
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7 comments:
Hmmmmm .... sorry .... stole it from the SAT QoftheD .... couldn't think of anything this morning!!
My answer is 3.
Car 1 = 2
Car 2 = 2
Car 3 = 2
The remaining 7 cars are filled with approximately 0.269 people per car. 7 Cars divided by 26 remaining people.
I'll go with PEF! D'uh English teacher here. If I don't have a computer or calculator, grades don't get averaged. I have kids, so they can do the math!!!!!
On a Monday ???....I have trouble enough with math and Mondays are even worse!!!!!!LOL
bree
PEF .... your wife is going to be embarassed to know you!!
The correct answer is 4.
You can not have partial people.
Car 1 = 2 total 2
Car 2 = 2 total 4
Car 3 = 2 total 6
Car 4 = 2 total 8
Car 5 = 4 total 12
Car 6 = 4 total 16
Car 7 = 4 total 20
Car 9 = 4 total 24
Car 9 = 4 total 28
Car10 = 4 total 32
And yes, this is the way I did it in Excel because I'm lazy and didn't want to remember the formula.
And I'm not embarassed at all.
Math is my strongest area. The english language, poetry, reading comprehension and non-sciences really mystify me, which is why PEF is my hero. He understand that which I get so frustrated with.
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